# 2-3-4 tree

Idea: all items are stored in a quaternary tree each node contains 1, 2, or 3 keys, all the non-leaves have 2, 3, or 4 children (respectively; hence the name) all the leaves are at the same level when a node overflows during insertion, it is split in two and the middle element is inserted to parent (a cascade of splits may occur) when a node underflows during deletion, it may borrow some elements from neighbouring nodes or, if the nodes are small, they may be merged guaranteed $O(\log n)$ time (in the worst case) for each dictionary operation; the height of a 2-3-4 tree is between $\log_2 n$ and $\log_4 n$ 2-3-4+ tree: items are only stored at leaves; the keys in internal vertices only serve as guides during the search

## Structure and balancing

In a 2-3-4 tree, every node has capacity to store 1, 2, or 3 keys. Internal nodes with $k$ keys have $k+1$ children (2, 3, or 4) and we call them accordingly, 2-nodes, 3-nodes, and 4-nodes:

All leaves must have the same depth - they have to be at the same level. This is achieved by splitting nodes that overflow and joining or reorganizing nodes that underflow.

Consequently, a 2-3-4 tree of height $h$ stores at least $2^h-1$ keys (if all nodes are 2-nodes) and at most $(4^h-1)/3$ keys (if all nodes are 4-nodes). This implies height between $\log_4(3n+1)\approx\frac12\log n$ and $\log (n+1)$.

### Insertion

When we insert a new key into a 2-node or 3-node, we just get a 3- or 4-node, which is OK.

However, when we insert a key into a 4-node, it overflows and we need to split it:

The procedure continues by inserting $z$ to the parent node. This may even start a cascade of overflown 4-nodes which ends either when the parent has enough capacity or we get to the top of the tree and create a new root (at this point the height of the whole tree increases by 1).

### Deletion

Assume we are deleting a key from leaf. (If not, we replace the key by its successor, which is in a leaf - the same trick we used in BST). When we delete from a 3- or 4-node, we just get 2- or 3-node, which is OK.

A problem occurs, when deleting from a 2-node which only has a single key, so after deletion, the node is empty and this is not allowed. There are two ways to fix it.

If a sibling next to it is a 3- or 4-node, we can borrow a key from it:

(A node may have two adjacent siblings - left and right. If any one of them is a 3- or 4-node, i.e. is full enough, we can borrow a key from it.)

We can’t use this trick if an adjacent sibling is a 2-node. In this case, we join it with a key from the parent node and recursively deal with deleting from the parent node (this may start a cascade of joins):

Here is the situation with 2 adjacent siblings, both 2-nodes:

In this case we join $x$ and $y$; the parent node keeps $z$ and we can stop.

Thus, the entire delete operation may involve a series of joins. It ends either with a share, or with join when parent is a 3- or 4-node, or continues all the way up to the root. In that case the final join deletes root and height of the tree decreases by 1.